-4x^2+20x=-24

Solution for -4x^2+20x=-24 equation:

-4x^2+20x=-24

We move all terms to the left:

-4x^2+20x-(-24)=0

We add all the numbers together, and all the variables

-4x^2+20x+24=0

a = -4; b = 20; c = +24;
Δ = b2-4ac
Δ = 202-4·(-4)·24
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*-4}=\frac{-48}{-8}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*-4}=\frac{8}{-8}
=-1
$